Question

我正与 Java文一道面对一个奇怪的问题,我正在建立一个jax数据库。数据库的标志性表格将数据发送给PHP控制器,同时提出分析要求/功能。我在标识页上有一个错误的显示器(称为错误Div)。差错离婚:

<div id="errorDiv" style="visibility:hidden; display:none">
...
</div>

当标识表中的用户名和密码领域都空出时,我需要PHP控制器做出反应,显示标识表,并运行 Java“DisemloginError()”功能,使错误变得明显,并在错误四中显示错误信息(请填平这两个领域)。显示仪表显示器码:

function DisplayLoginError()
{
document.getElementById( errorDiv ).style.visibility="visible";
document.getElementById( errorDiv ).style.display="block";
document.getElementById( errorDiv ).innerHTML = "<?php echo $loginerror; ?>";
}

The php controller Code is:

if(isset($_REQUEST[ login ]))
{
if(isset($_REQUEST[ username ]) && isset($_REQUEST[ password ]))
    {
    .....Both the fields are filled...
    }
else   /*===Error:Any of the username or password field has  been left empty====*/
    {
    $loginerror= Please fill both the Fields to login. ;
    include $_SERVER[ DOCUMENT_ROOT ]. hospitalincludescollegedatalogin-form.html.php ;
    }
}

现在的问题是,由于大多数 j印事件是用户错开的,因此无法做到这一点。就时间而言,我指派了标号为湿度活动,在启动显示仪表显示仪表显示仪表显示错误。

<form onmouseover="DisplayLoginError()"> ..... </form>

But its not the proper solution. I need an event which can run this function while loading only the login div not the whole page. I can t use the onload event here as its an ajax Database where the main page remains still only div s change. May be the time events can be used for this purpose... I am not sure...May be there is some better solution... How can I do it with ajax?

Answer 1

你们可以在javascript中利用失去的焦点活动。我可以清楚地理解你提出的问题。因此,这只是一项建议。

<div id= errorDiv  >
</div>
Username : <input type="text" name="username" id="uname" onBlur="checkUsername();">
Password : <input type="text" name="password" id="pword" onBlur="checkValues();">

<script type="text/javascript">
function checkValues()
{
    uname = document.getElementById( uname ).value;
    pword = document.getElementById( pword ).value;
    if(uname=="" || pword=="") {
        document.getElementById( errorDiv ).innerHTML="Please fill both the fields";
    }else{
        document.getElementById( errorDiv ).innerHTML="";
    }
}
function checkUsername()
{
    uname = document.getElementById( uname ).value;
    if(uname==""){
        document.getElementById( errorDiv ).innerHTML="Please enter username";
    }else{
        document.getElementById( errorDiv ).innerHTML="";
    }
}
</script>

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