Question

我试图把我的照片带入海峡和地貌。我的指挥是,对小pe的规模进行打印:

identify -format  %w %h
  1234.jpg 
1067 1600

如果我用纸张书写,把所有景象推向另一个侧面,那么我会期望它像现在这样。

#!/bin/bash
# loop through file (this is psuedo code!!)
for f in ~/pictures/
do
 # Get the dimensions (this is the bit I have an issue with)
 identify -format  %w %h
  $f | awk # how do I get the width and height?
 if $width > $hieght
  mv ~/pictures/$f ~/pictures/landscape/$f
 fi
done

看一看一页,但我看上去看一看。

Answer 1

你们不需要AWK。与此类似:

identify -format  %w %h
  $f | while read width height
do
    if [[ $width -gt $height ]]
    then
        mv ~/pictures/$f ~/pictures/landscape/$f
    fi
done

Answer 2

您可使用<条码>。

# WxH is a array which contains (W, H)
WxH=($(identify -format  %w %h
  $f))
width=${WxH[0]}
height=${WxH[1]}

Answer 3

format=`identify -format  %w %h
  $f`;
height=`echo $format | awk  {print $1} `;
width=`echo $format | awk  {print $2} `;

Answer 4

现在用于“盲目、明显”的球:

# use the identify format string to print variable assignments and eval
eval $(identify -format  width=%w; height=%h  $f)

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