Question

我希望我的LCD显示“Voltage=(传感器Value)”,但现在,我获得该方案承认这一价值的唯一途径是,如果我把它 put在一旁的话。但是,当我把它放入一个坡道时,整个屏幕上填满了1、2、3、4或5个,取决于立立强计的地点。

If I don t have it in a loop then whatever setting the potentiometer is on is what will pop on the screen and will not change if potentiometer is turned.

我怎么能够把休闲结果置于休闲之外,以便我能够“(Voltage=传感器Value)”?

Here s my program:

#include <Wire.h> 
#include <LiquidCrystal_I2C.h>

LiquidCrystal_I2C lcd(0x27,16,2);  

void setup()
{
    lcd.init();                      
    lcd.backlight();
    int sensorPin = A0;
    int sensorValue = 0;
    sensorValue = 0.004882812 * analogRead(sensorPin) + 1;
    lcd.print("Voltage=");
}

void loop()
{
    int sensorPin = A0;
    int sensorValue = 0;
    sensorValue = 0.004882812 * analogRead(sensorPin) + 1;
    lcd.print(sensorValue);
}

Answer 1

This is what I came up with last week. Thanks for all the advice guys!

#include <Wire.h> 
#include <LiquidCrystal_I2C.h>
LiquidCrystal_I2C lcd(0x27,16,2);  

void setup() {}

void loop()
{ lcd.init();                      
lcd.backlight();

int VoltsInput = A0;
int VoltsRange = 0;
int VoltsPercent = 0;

VoltsRange = (5.0/1023.0) * analogRead(VoltsInput);
VoltsPercent = (((5.0/1023.0) * analogRead(VoltsInput)) / 5) * 100;

lcd.print(VoltsRange);
lcd.print("V    ");

lcd.print(VoltsPercent);
lcd.print("%");}

Answer 2

规定它属于 lo,并使用一种延迟功能,使贵方案能够读出每秒钟而不是每秒钟的pot。

Answer 3

It sounds like print() is clearing the screen of previous data every time it is called (although the relevant documentation and library code available here and here is unclear).

如果是的话,你需要印刷<代码>。 Voltage= string in the loop with the 传感器 Value. 1. 修改你的法典如下:

#include <Wire.h> 
#include <LiquidCrystal_I2C.h>

LiquidCrystal_I2C lcd(0x27,16,2);  
int sensorPin = A0;

void setup()
{
    lcd.init();                      
    lcd.backlight();
}

void loop()
{
    int sensorValue = 0.004882812 * analogRead(sensorPin) + 1;
    String display = "Voltage=";
    display += sensorValue;
    lcd.print(display);
}

友情链接