Question

How to apply floor function to float or double values to get integer.I got double Value:4.4497083717E10 float Value:4.4497084E10 out of my function.I got floor values as Floor of double:4.4497083717E10 Floor of float:4.4497084416E10.Is there a possibility that floor results in a integer??

Answer 1

。底线是否会导致愤怒?

http://docs.oracle.com/javase/6/docs/api/java/lang/Math.html

That said, the documentation for the method declares that the returned value is equal to an integer. So simply casting the returned result to an int will always give you the output you expect.

(假设你的结果是多种多样的。) www.un.org/spanish/ecosoc 可持有<代码>int可代表的较大数目。 http://docs.oracle.com/javase/specs/jls/se7/html/jls-5.html#jls-5.1.3”rel=“nofollow” 技术细节上的微量减量换算。您不妨对您的数据进行约束,以确保其始终能够转换为<代码>int。

Answer 2

4.4497083717E10过于庞大,不能成为<条码>int,你必须投到<条码>。

长期以来,这种双重做法的整部分与<>Math.底对可长期代表的价值加以表述。 i.e.

long l = (long) Math.floor(4.4497083717E10);

这与

long l = (long) 4.4497083717E10;

System.out.println((int) Math.floor(4.4497083717E10));
System.out.println((long) Math.floor(4.4497083717E10));
System.out.println((long) 4.4497083717E10);

印刷

2147483647   -- due to an overflow
44497083717
44497083717

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