Question

是否有办法知道,在不使用管理图书馆的情况下,用“货物”进行扼杀吗?

Maybe using strcpy, strlen, ecc.

Answer 1

str.length() >= 7 && str.substr(str.length() - 7) == "goodbye"

也可使用boost:ends_with , 这可能更为有效,因为它没有分配像。

I could make the standard library version a little more efficient like this:

str.length() >= 7 && std::equal(str.end() - 7, str.end(), "goodbye");

Actually, now that I typed that out, I realize it s not as cumbersome as I thought it would be, so that should probably be preferred to the first version.

Answer 2

是的,这是可能的,它采取了两个步骤:

Use strlen to get the length and see if it s at least 7. If not, no match.
Use the length to examine the last 7 characters of the string and compare them using strcmp.

Answer 3

#include <string>

int main(void) {
    std::string a="hellogoodbye";
    size_t pos = a.rfind("goodbye");
    if(pos != string::npos && pos == a.length() - 7) std::cout << "true";
}

Answer 4

In C:

bool ends_with(char const * string, char const * ending) {
    size_t const slen = strlen(string);
    size_t const elen = strlen(ending);
    return slen >= elen && memcmp(string+slen-elen, ending, elen) == 0;
}

C++:

bool ends_with(std::string const & string, std::string const & ending) {
    return string.length() >= ending.length() && 
           std::equal(ending.rbegin(), ending.rend(), string.rbegin());
}

友情链接