Question

I have the following setup, abridged for brevity:

public abstract class AuditableEntity
{
    public int Id { get; set; }
    public Login Login { get; set; }  // Login that create this identity.
}

public class Login: AuditableEntity
{
    public Security Security { get; set; }
    public Guid SessionGuid { get; set; }
}

public class Security: AuditableEntity
{
    public string UserName { get; set; }
    public string PasswordHash { get; set; }
}

如今,在<代码><<<0> /代码>上不要求实体本身填写。事实上,它不属于该表,因此,我忽略了:

modelBuilder.Entity<Login>().Ignore(l => l.Login);

我想,正如所有其他表格所要求的那样,但当我如在<代码>上尝试和要求时。用户:

modelBuilder.Entity<Security.Security>().Property(p => p.Login).IsRequired();

我收到一个汇编错误,即“为了将其用作参数T, Log必须是不可损失的价值类型”。我注意到,我获准在前面的<代码>Ignore中将其用作参数T,因此,我认为这是其他一些隐蔽的T。

My immediately apparent solutions are not very elegant:

Use an FK value and not a reference poperty for Login in in AuditableEntity.
Create a new base class without Login, and another derived from that that adds Login, then inherit my Login class from the highest base, and all other classes from its immediate descendant.

是否有更好的办法这样做?

Answer 1

你们正在将财产合成物用于土质。您实际上希望使用Nav Property syntax,例如。 HasRequired(t=>t. Carloin)。 WithMany( or some similar

See http://msdn.microsoft.com/en-us/library/hh295843(v=vs.103).aspx, and the Configuring a Relationship with One Navigation Property section

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