Question

我有一份名为<代码>的文件。除含有“1”或“城市”的字句外,我谨删除每一行,包括“中心”、“农场”或“中间”等。

The list of deletions and exceptions is quite long.
The files are in UTF-8.

我怎么能删除其中至少一个字的每一个行文,而不要删除那些有某些例外的行文?

Answer 1

这或许有助于你:

sed -i  /center of|farm|middle of/{/①|city/!d}  file1.txt

或

sed -i  /center of/ba
        /farm/ba
        /middle of/ba
        b 
        :a
        /①/b
        /city/b
        d  file1.txt

如果有<代码>序号和,则使用:



sed  /*exceptions*/{h;s/.*/:a/p;d}
    x
    /./{x;s|.*|/&/b|p;$!d;s/.*/d/;q}
    x
    s|.*|/&/ba|  words.txt - <<<"*exceptions*" exceptions.txt > file.sed
sed -i -f file.sed file1.txt

Answer 2

sed -r  /①|city/{p;d};/center of|farm|middle of/d  file1.txt

Answer 3

sed  /blacklist/{/whitelist/p;d}  file

删除黑名单,但列入白色名单者除外:

echo -e "a b
b c
c d
d e
e f" | sed  /c|d/{/a|b/p;d}

印刷

a b
b c
e f

每一行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各行各

友情链接