Question

$arr1 = array ("llo" "world", "ef", "gh" );

What s the best way to check if $str1 ends with some string from $arr1? The answer true/false is great, although knowing the number of $arr1 element as an answer (if true) would be great.

例:

$pos= check_end("world hello");//$pos=0; because ends with llo
$pos= check_end("hello world");//$pos=1; because ends with world.

是否比对<条码>所有内容进行对比更好/具体/专门的方法?

Answer 1

页: 1

function check_end($str, $ends)
{
   foreach ($ends as $try) {
     if (substr($str, -1*strlen($try))===$try) return $try;
   }
   return false;
}

Answer 2

见startsWith() and endWith() functions in PHP 。

使用

$array = array ("llo",  "world", "ef", "gh" );
$check = array("world hello","hello world");

echo "<pre>" ;

foreach ($check as $str)
{
    foreach($array as $key => $value)
    {
        if(endsWith($str,$value))
        {
            echo $str , " pos = " , $key , PHP_EOL;
        }
    }

}


function endsWith($haystack, $needle)
{
    $length = strlen($needle);
    if ($length == 0) {
        return true;
    }

    $start  = $length * -1; //negative
    return (substr($haystack, $start) === $needle);
}

产出

world hello = 0
hello world = 1

Answer 3

Pretty sure this will work. Define your own "any" function, which takes an array and returns true if any of its values evaluate to true, and then use php s array_map function to do the equivalent of list-comprehension to construct an array to pass to it. This could instead be combined into one function, but you ll probably find the "any" function useful elsewhere in its own right anyway.

if (!function_exists( any )) {
    function any(array $array):bool {
        return boolval(array_filter($array));
    }
}

function check_end (string $needle, array $haystack):bool {
    return any(
        array_map(
            function (string $end) use ($needle):bool {
                return str_ends_with($needle, $end);
            },
            $haystack,
        )
    );
}

友情链接