Question

Having the next XML(Idatzi.xml) :

<?xml version= 1.0  encoding= ISO-8859-1 ?>
<!DOCTYPE markables SYSTEM "markables.dtd">
<markables>
<markable id="markable_1" atrib="yes" span="word_1..word_4"> </markable>
<markable id="markable_2" atrib="no" span="word_6..word_7"> </markable>
<markable id="markable_3" atrib="yes" span="word_10..word_24"> </markable>
</markables>

以及下一个PHP代码:

<?php

$xmlIdatziDok = new DOMDocument();
if($xmlIdatziDok->load("Idatzi.xml") === FALSE){die( Error );}
$xPath_IdatziDok = new DOMXPath($xmlIdatziDok);

foreach ($xPath_IdatziDok->query( //markables/markable ) AS $Idaztekoa)
{
  $IdaztekoaID = $Idaztekoa->getAttribute( id );
  $IdaztekoaAtrib = $Idaztekoa->getAttribute( atrib );

    if($IdaztekoaAtrib != "yes")
    {
      $Idazteko->Attribute( atrib ) = "yes";      
    }
}

I would like to know how to correctly write the next line of code in the PHP code:

$Idazteko->Attribute( atrib ) = "yes";

这显然是错误的写法。我要做的是,将可加标的2号“无”改为“有”。任何想法?

Answer 1

You can find this information in the documentation.

$Idaztekoa->setAttribute( atrib ,  yes );

Answer 2

利用Xpath query直接选择你想要改变和操纵的一切属性:

foreach($xp->query( /markables/markable/@atrib[. != "yes"] ) as $attrib)
{
    $attrib->nodeValue =  yes ;
}

并且已经这样做。实例:

$xml = <<<XML
<?xml version= 1.0  encoding= ISO-8859-1 ?>
<!DOCTYPE markables SYSTEM "markables.dtd">
<markables>
    <markable id="markable_1" atrib="yes" span="word_1..word_4"> </markable>
    <markable id="markable_2" atrib="no" span="word_6..word_7"> </markable>
    <markable id="markable_3" atrib="yes" span="word_10..word_24"> </markable>
</markables>
XML;

$doc = new DOMDocument();
$doc->loadXML($xml);
$xp = new DOMXPath($doc);

foreach($xp->query( /markables/markable/@atrib[. != "yes"] ) as $attrib)
{
    $attrib->nodeValue =  yes ;
}

echo $doc->saveXML();

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