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2. 与点数合并,以建立C/c++的结构
原标题:Confusion with pointer to structure in c/c++
  • 时间:2012-04-26 22:26:49
  •  标签:
  • c++
  • c

我试图消除某些混淆之处,把结构用作阶级成员。 我写道,尽管该方案汇编了坠机。 您能否说一下,在以下法典中我做了什么错误?

#include<stdio.h>
#include<string.h>

struct a{
    int s;
    int b;
    char*h;
};

class test
{
public:
    a * f;
    void dh();
    void dt();
};

void test::dh()
{
    a d;
    d.s=1;
    d.b=2;
    d.h="ffdf";
    f=&d;
}

void test::dt()
{
    printf("%s %d %d",f->h,f->b,f->s);
}

int main()
{
    test g;
    g.dh();
    g.dt();
    return 0;
}
最佳回答
void test::dh()
{
    a d; <--
    d.s=1;
    d.b=2;
    d.h="ffdf";
    f=&d; <--
}

页: 1 一旦该功能结束,该物体就不属于范围,你再留下一个ling点。

问题回答

最大的问题是,到<代码>h(>>>>回归时,<代码>d已不复存在。 而不是a d; in dh(), 您需要f = new a(); f.s=1; f.b=2, f.h=“ffdf”;

测试:后,你指定了公共点人,而不是地方变量的地址。 当g.dh()、 退出时,d地址不再有效,这就是为什么在g.dt();中提及f的字句失效。





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