Question

In my sample program in 1stscreen i have one input field,based on this input i have to show a list view(which is another activity)how can i implement that.I am new to android.Here is my code.

这是在点击后:

if(text1.getText().toString().equals("subbu"))
            { 
                startActivity(new Intent(Listview));
//              Toast.makeText(Sampleprojectsubbu1Activity.this,"Name:"+text1.getText().toString(), Toast.LENGTH_LONG).show();              
            }

清单如下: 就抽样而言,我提供了一些不想要的阵列。

public class Listview extends ListActivity 
{
    public void onCreate(Bundle savedInstanceState) 
    {
        super.onCreate(savedInstanceState);
        setListAdapter(new ArrayAdapter<String>(this, R.layout.list_item, COUNTRIES));

    }
    static final String[] COUNTRIES = new String[] 
            {
                   "XXXXX","YYYYYY"

            };

}

Answer 1

Wrong:

 startActivity(new Intent(Listview));

正确开端方式活动:

startActivity(new Intent(CurrentClassName.this, DestinationClassName.class));

Update:

了解更多关于意向、检查和读到以下条款:

Answer 2

主要活动:

Intent myIntent = new Intent(this, ListView.class);
myIntent.putExtra("variableName", variableValue);
this.startActivity(myIntent);

注

Bundle extras = getIntent().getExtras();
if (extras != null) {
String varName = extras.getString("variableName");//Datatype can be any
}

Answer 3

你们必须这样做,代之以代号。

1. 启动(新加入(Listview);

启动(MainActivty.this,ListView.class);

此外,必须明确增加这一新活动。

Update:

友情链接