Question

我想逐字逐字删除,我尝试:

find temp -type d | while read DIRNAME
do
    sed -i  /abcd1/,/abcd2/d  ~/Desktop/$DIRNAME/.x
done

问题在于,我只想消除第一次发生这种情况,而是要消除这种情况。

sed -i  0,/abcd1/,/abcd2/d  ~/Desktop/$DIRNAME/.x

没有工作。

Answer 1

sed -ie  bb; :a q; :b s/from/into/; ta  test.txt

bb; — branch to the b mark (skipping the quit command);
:a q; — a mark with the quit command;
:b s/from/into — b mark with substitution;
ta — jump to a mark if substitution is successful;
; — command delimiter in sed.

希望会有所帮助。

Answer 2

一种方式:

sed -e  /3/,/6/ { /6/ ba ; d }; b ; :a ; $! { N ; ba }; s/[^
]*
//

<>strong>EDIT,解释:

/3/,/6/         # Range between line that matches  3  and other line that matches  6 .
{
  /6/ ba        # When matches last line of the range, goto label  a .
  d             # Delete each line in the range.
}
b               # This command will be executed in lines until first match in the 
                # range. It prints the line and begin loop reading next one.
:a              # Label  a .
$!              # While not found last line ...
{ 
  N             # Append next line to current pattern space.
  ba            # Go to label  a . Enter a loop reading each line until last one.
}
s/[^
]*
//    # Remove until first  
  (content of last line of the range) and print 
                # the rest.

www.un.org/spanish/ga/president

infile:

赞成:

sed -e  /3/,/6/ { /6/ ba ; d }; b ; :a ; $! { N ; ba }; s/[^
]*
//  infile

Output (only deletes lines between 3 and 6 once):

Answer 3

这或许有助于你:

sed  /word1/!b;:a;/word1.*word2/{s///;tb};$!{N;ba};:b;$!{n;bb}  file

以上用词,用行各行各行各行:

sed  /block1/,$!b;x;/./{x;b};x;/block1/,/block2/{/block2/h;d}  file

EDIT:

删除<代码>第1行,但只有不止一次出现:

 sed  /word1/!b;:a;/(word1).*(word2)(.*1.*2)/{s//3/;tb};$!{N;ba};:b;$!{n;bb}  file

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