Question

我想以html的形式验证电子邮件地址。我很少了解这方面的情况。

审定非常简单,仅与any_symbols@any_symbols. 2_to_car_symbols格式相匹配。

这里是试图使用<代码>+@.+.{2,8}$的Im。然而,它的确做了大量工作,它验证了模式any_symbols@four_symbols。

注:不担心这种简单的验证,在服务器一米处,filter_var(php)上,并寄给电子邮件。 • 在投入电子邮件地址时,只需要使纽顿能够形成某种衰弱模式:

EDIT Those patterns "any_symbols..." I ve mentioned in question are just textual representation of what I m trying to input. This is not what I type in input field :) Usually I type "[email protected]", or "[email protected]" and etc. :)

<><><><>>>>>> 实际代码:

   var email_regex = new RegExp("^.+@.+..{2,8}$");
if ($target.val().match(email_regex) !== null){
    $button.removeAttr( disabled ).removeClass( disabled );
}
else{
    $button.attr( disabled ,  disabled ).addClass( disabled );
}

EDIT3 *Found the problem!* It wasn t the regex itself, it was how I passed regex to Regex function... it should be

 new RegExp(/^.+@.+..{2,8}$/);

不适用

new RegExp("^.+@.+..{2,8}$");

正如我说过的那样,这件事对我来说是很新的:

Answer 1

简言之,真正的电子邮件地址的管理机构并不简单,因为它应当符合《海运法》的标准。

然而,如果为你工作,我就没有问题:

// The regex: /^[_a-z0-9-]+(.[_a-z0-9-]+)*@[a-z0-9-]+(.[a-z0-9-]+)*(.[a-z]{2,4})$/

// To test it:
var regex = new RegExp(/^[_a-z0-9-]+(.[_a-z0-9-]+)*@[a-z0-9-]+(.[a-z0-9-]+)*(.[a-z]{2,4})$/);

if( regex.test( your_string ) ){ ... } // returns true if valid

如果你真的需要接受“纽约”的标志,你可以使用Birei所贴的reg。

Answer 2

Not a Javascript expert, but with your definition of any_symbols@any_symbols.two_to_eight_symbols I think this could work:

^[^@]+@[^.]+..{2,8}$

Answer 3

你们需要逃脱鞭::

 any_symbols@four_symbols .match( ^.+@.+\..{2,8}$ );
                                        ^^

否则, Java的成文如下:.,作为不知名的逃跑顺序和。

For characters not listed [...] a preceding backslash is ignored, but this usage is deprecated and should be avoided.

(Damn,这很难找到......)

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