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原标题:retainAll changes the last element
List<Left> resultList = lists.iterator().next();
    for (Iterator iterator = lists.iterator(); iterator.hasNext();) {
        List<Left> list = (List<Left>) iterator.next();         
        resultList.retainAll(list);
    }

    /*for (Left left : resultList) {
         System.out.println(left.getData());
    }*/

    for (Left left : mLeft) {           
        ArrayList<Left> mTempList = left.getArray();    
        for (Iterator iterator = mTempList.iterator(); iterator.hasNext();) {
            Left left2 = (Left) iterator.next();
            System.out.println(left2.getData());
        }
    }

I am trying to find out the common elements , my original list is getting changed.I mean only last element gets changed when I print the lists. Any suggestions.

问题回答

<代码>代号:在上列第1部分。

第4行:在不改动<条码>、代号/代码”的情况下,请在<条码>上注明第1项标的<条码>。

您不妨考虑设立新的<条码>。 清单和编号;Left> 反对核对共同内容,而是在一开始,而不是你如何宣布resultList:

List<Left> resultList = new List<Left>();
resultList.addAll ((List<Left>) lists.iterator().next());
...

然后,你想要利用结果。 在你打印内容时,列入最后记录。

请注意,如果你空出空,你仍然假设<代码>/代码>至少有一个要素。





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