Question

I have the code below. Now I want to run an if-else statement on it, but it s not working. Any idea with this?

var num1 = $( #id1 ).val(); 
var num2 = $( #id2 ).val();

var newVal = (num1+2)*(num2/4);
var nextVal =(num1+4)*(num2/2);
var newArr = new Array();
newArr.push(newVal);
newArr.push(nextVal);

newArr.sort();

if(newArr.get(0)==newVal)
$("body").html("<p>works fine!</p>");
else $("body").html("<p>works awfully!</p>");

Answer 1

你们宣布“Var”和资本五。

Var newVal = (num1+2)*(num2/4);

此外,出入阵列的内容有[指数],而不是植被(指数)

页: 1

  var num1 = 50;   
  var num2 = 100;

  var newVal = parseInt((num1+2)*(num2/4));
  var nextVal =parseInt((num1+4)*(num2/2));
  var newArr = new Array();
  newArr.push(newVal);
  newArr.push(nextVal);

  newArr = newArr.sort(function(a,b){return a - b});

  if(newArr[0]==newVal)
    $("body").html("<p>works fine!</p>");
  else
    $("body").html("<p>works awfully!</p>");

Answer 2

Just use newArr[0] und newArr.get(0)

Answer 3

<代码>val将重载体,因此你可能不得不改成编号。您可以使用非正常加操作器:

var num1 = +$( #id1 ).val(); // Now you get 5 instead of "5" 
var num2 = +$( #id2 ).val();

//The problem shows up here when you are doing string concatenation instead of addition in the first set of parenthesis
var newVal = (num1+2)*(num2/4);

if(newArr[0]==newVal) // .get is for jQuery collections, just use brackets on an array

Answer 4

Try this

var num1 = 50;   
  var num2 = 100;

  var newVal = (num1+2)*(num2/4);
  var nextVal =(num1+4)*(num2/2);
  var newArr = new Array();
  newArr.push(newVal);
  newArr.push(nextVal);

  newArr.sort();

  if(newArr[0]==newVal)
    $("body").html("<p>works fine!</p>");
  else
    $("body").html("<p>works awfully!</p>");

友情链接