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我有一阵列。

现在,我想将阵列第17位的价值与阵列第1位的位置的价值区分开来,然后是第18位。成果应当建立一个新的阵列。

然后,我想弄清新阵列的所有价值,如果两个或两个以上连续的数值大于1.2,我还要补充一下,把新阵列的最后一个价值与所有连续价值分开。如果一个数值为1.2,下一个数值为0.8,则不应改变阵列的数值。

我的守则是:

a = [1,2,3,4,5,9,5,13,14,17,19,23,19,34,46,12,13,45,46,67,78,79]

b = Array.new
c = Array.new

a.each_cons(18) { |c| b.push(c[17]/c[0] }

Do you have an idea how to implement the condition?

Answer 1

我认为这样做,尽管我有选择地从你的问题中解释过一些事情。具体来说,在“所有连续价值之行”中,“增长”指的是每一条基点的碎块? Ditto for “all persistent Value”

catch (:done) do
  for i in 2..b.length do
    b.each_cons(i) do |d| 
      for j in 2..d.length do 
        d.each_cons(j) do |g|
          if g.all? { |g| g > 1.2 }
            c = b.map { |f| f + (d[0].to_f/d[i-1].to_f) }
            break
          end
          if !c.empty? then throw :done end
        end
      end
    end
  end
end

puts c

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