Question

我有一个表格,主要是每个用户的活动记录,我想显示,自上一次活动以来,用户已经花了多少时间。

学历:

SELECT message_log.log_phone_number, message_log.log_updated
FROM message_log
WHERE message_log.log_mode = “inbound”
GROUP BY  message_log.log_phone_number

结果

415407XXXX  2012-03-07 13:34:14      
434242XXXX  2012-03-07 16:00:42          
434465XXXX  2012-03-07 14:49:15          
434989XXXX  2012-03-07 15:30:22          
757615XXXX  2012-03-07 15:30:54          
804651XXXX  2012-03-07 14:13:04          
920917XXXX  2012-03-07 15:11:28

Problem: My 结果 is showing the oldest Time Stamp, and I want the most recent. Is there some way to ORDER within the GROUP BY?

Answer 1

SELECT message_log.log_phone_number, max(message_log.log_updated) 
FROM message_log 
WHERE message_log.log_mode = “inbound” 
GROUP BY message_log.log_phone_number

Answer 2

你们只需要一个“彩虹”。

SELECT message_log.log_phone_number, 
MAX(message_log.log_updated) as log_updated
FROM message_log
WHERE message_log.log_mode = “inbound”
GROUP BY  message_log.log_phone_number

友情链接