Question

我试图利用奥乌特进行核查。我的榜样守则是:

ArrayList <NameValuePair> params = new ArrayList<NameValuePair>();
  boolean flag=false;
  URL url;

  String oauth_nonce="q14F5ApN4Ka5RJGbYgabXwMSZ4BxVrlNGedN9zoFAoi3rc7dpLjIgri1erAAriPu";
  String oauth_timestamp="1336069726";
  String signatureString =
    URLEncoder.encode("device_id=id_here")
    +URLEncoder.encode("&device_type=psw_here")
    +URLEncoder.encode("&oauth_consumer_key=consumer_key_here...&oauth_nonce=" +
      oauth_nonce+
      "&oauth_signature_method=HMAC-SHA1&oauth_timestamp=1336069726&oauth_version=1.0");

  String percent_encoded_url = URLEncoder.encode("http://www.example.com");
  String signatureBaseString = "POST"+
    "&"+percent_encoded_url+
    "&"+signatureString;

  String oauth_signature=URLEncoder.encode(computeHmac(signatureBaseString, "aWAQTWR7VvHapaNhWBCL0VaUdGN2xzN4&"));

  String headerValue ="OAuth "+
    "oauth_consumer_key=""+"consumer_key_here..."+"","+
    "oauth_signature_method="HMAC-SHA1"+"","+
    "oauth_signature=""+oauth_signature+"","+
    "oauth_timestamp="1336069726"+"","+
    "oauth_nonce=""+oauth_nonce+""," +        
    "oauth_version="1.0"+""";


  HttpPost httppost = new HttpPost("http://www.example.com/");

  httppost.setHeader("Content-Type","application/x-www-form-urlencoded");
  httppost.setHeader("Authorization",headerValue);
  HttpEntity httpentity = new UrlEncodedFormEntity(params);

  HttpClient httpclient = new DefaultHttpClient(clientConnectionManager, httpparams);

  StringBuilder sb = new StringBuilder();
  try {

   HttpResponse response = httpclient.execute(httppost);

当我发出要求时,总是说Bad Apmat。我不知道奥乌特。我对我的错误没有想法。谁能指导我正确方向?

Answer 1

它认为,你正在以正确方式生成签名,但服务器用通用<代码>信号表示,因为:

www.un.org/chinese/ga/president 你们需要为每一项请求随机产生一种新的非礼。

<>秒钟<>,每次申请,均需在万国邮联的目前时间。如果奥阿瑟公司得到正确执行,它将允许在很近的将来或过去修建一些时间。因此,确保你的锁定正确无误。

从我能告诉你的签字一代看,至少如果你试图找回象征性的请求,你就会看上去。与以上两点相提并论,让我知道:

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