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Java:URI的非法性质
原标题:Java: Illegal character in URI

我试图要求Gapogles大地皮使用这一源代码。

client = new DefaultHttpClient();
    HttpGet get=new HttpGet(uri);
        try {
            HttpResponse response = client.execute(get);
            int statusCode = response.getStatusLine().getStatusCode();
             if (statusCode == 200 ){
                    HttpEntity entity = response.getEntity();
                    InputStream is = entity.getContent();
                    try {
                        XMLReader parser = XMLReaderFactory.createXMLReader();
                        parser.setContentHandler(gh);
                        parser.parse(new InputSource(is));
                    } catch (IllegalStateException e) {
                        e.printStackTrace();
                    } catch (SAXException e) {
                        e.printStackTrace();
                    }
             }
        } catch (IOException e) {
            e.printStackTrace();
        }

Is the URI like this http://maps.googleapis.com:80/maps/api/geocode/xml?address=Königstraße, Berlin&sensor=false

一个例外是:非法性质!

How can I escape ä,ü,ö,ß and the blanks? I tried the java.net.URLEncoder with ISO-8859-1 as encoding without success :(

i

最佳回答

You need to URL-encode the invididual request parameter value with UTF-8, not the entire URL and also not with ISO-8859-1.

String url = "http://maps.googleapis.com:80/maps/api/geocode/xml"
    + "?address=" + URLEncoder.encode("Königstraße, Berlin", "UTF-8") 
    + "&sensor=false";
问题回答

K%C3%B6nigstra%C3%9Fe UTF-8 编码也将发挥作用。





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