Question

我为我的申请创造了一个开端。

I can t figure how to get current route / tell if the page / "Call" is active.

The Code in index.scala.html

@if(page.getTotalPageCount() > 0){
<div class="pagination">
    <ul>
    @for(i <- 0 to page.getTotalPageCount()-1){
        <li@if(@routes.NewsHandler.index(i) == ?){ class="active"}><a href="@routes.NewsHandler.index(i)">@(i+1)</a></li>
    }
    </ul>
</div>
}

基本上如此。

if(@routes.NewsHandler.index(i) == ?){ class="active"}

任何想法?

EDIT, i found a working solution:

@if(request().path().toString().equals(routes.NewsHandler.index(i).toString())){ class="active"}

Answer 1

目前,没有标准方法了解目前的<代码>Handler。

友情链接