Question

How to create an inline variable in the Play framework 2.x Scala template? Path from the Play s guide is not clear to me:

@defining(user.firstName + " " + user.lastName) { fullName =>
  <div>Hello @fullName</div>
}

Answer 1

First you don t create a variable but a value meaning it s read only.

在你的例子中,你创建了一个价值<代码>fullName,可在曲线方括号内查阅。

@defining("Farmor") { fullName =>
  <div>Hello @fullName</div>
}

页: 1

在你的模板中界定全球可获取的价值,只是包括你 brackets的括号。

E.g.

@defining("Value") { formId =>
  @main("Title") {
    @form(routes.Application.addPost,  id -> formId) {
      @inputText(name = "content", required = true)
      <input type="submit" value="Create">
    }
  }
}

例如,您可使用<代码>formId。

Answer 2

If you don t want to use the @defining syntax you can define a reusable block which will be evaluated every time you use it:

@fullName = @{
  user.firstName + " " + user.lastName
}

<div>Hello @fullName</div>

With this same syntax you can also pass arguments to the block: https://github.com/playframework/Play20/blob/master/samples/scala/computer-database/app/views/list.scala.html

Answer 3

从样本中抽取密码,很容易跨越你的碎块,那么你可以使用@fullName。具有价值的变量:

user.firstName + " " + user.lastName

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