这一网站relative placehtml的头盔与所有平台的所有浏览器完全一致? 任何标准?
Location: some_script.php?la=2&po=2030
我指的是,它总是会改用一些文字。 现行继承人所在地点?
这一网站relative placehtml的头盔与所有平台的所有浏览器完全一致? 任何标准?
Location: some_script.php?la=2&po=2030
我指的是,它总是会改用一些文字。 现行继承人所在地点?
标准是:
header( Location: http://www.mywebsite.com/yourpage.php?id=32 , TRUE, 302);
但是,为了回答你的问题,如果你没有首先或完全的URL的话,它会改用现在的圆页X。
在此,我想建议你们为你们的每一个网站做些什么。 在你的主要档案中(主文件S.C.S.R.S.C.S.M.S.M.S.M.S.M.S.M.S.M.S.M.S.M.S.M.S.M.S.M.S.S.M.S.M.S.M.S.M.M.S.M.S.M.S.M.A.S.M.M.K.,在你的主要档案中(主文件S.G.和M.S.M.S.S.)制造了类似的东西。
define( URL , http://www.mywebsite.com/ );
因此,当你制造方向、联系或关系时,你会这样做:
header( Location: .URL. yourpage.php?id=32 , TRUE, 302);
EDIT:2017年11月。 如下文“jordanbtucker”所述,“吉普林特”光谱已于2014年6月更新(该员额从2012年起),允许位于定位头上的相对URIs。
最好的办法是:
$server = $_SERVER[ SERVER_NAME ];
$port = isset($_SERVER[ HTTP_X_FORWARDED_PORT ]) && !empty($_SERVER[ HTTP_X_FORWARDED_PORT ]) ? : . $_SERVER[ HTTP_X_FORWARDED_PORT ] : ;
$protocol = $_SERVER[ PROTOCOL ] = isset($_SERVER[ HTTP_X_FORWARDED_PROTO ]) && !empty($_SERVER[ HTTP_X_FORWARDED_PROTO ]) ? "https://" : "http://";
$destination = some_script.php?la=2&po=2030 ;
$url = $protocol . $server . $port . $destination;
header( Location: . $url, TRUE);
在分配任何实际产出之前,必须召集该负责人。
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