我有一个应该容易回答的问题。
我有一个称为<代码>项目的表格,主要为<代码>项目Id。
下表为<代码>项目Resources和。 Id作为外国钥匙,加上用户和时间(代表指定从事项目工作的用户)的田地
附件三 (用户用于记录项目实际使用的小时用户) 项目Id作为外在钥匙和外地<代码> 用户/代码
所需要的是,我要展示<代码>项目Id,BudgetedHours ( ProjectResources table)和ActualHours(timesheettriesEn的表格);但我要列入下列情况:
a 用户被分配到项目上,但没有工作(在这种情况下,预算时间应当具有价值,实际时间应为零)。
a 用户没有被分配到项目上,但已经投入使用(在这种情况下,预算受益人应为零,实际受益人应具有价值)
a 用户既被分配到项目上,也已经投入工作(既包括预算受益人,也具有价值)。
有些人能否将我引向T-SQL的发言,以取得这种结果?
你们可以尝试:
SELECT p.ProjectId,
(CASE WHEN pr.[User] Is NULL THEN te.[User] ELSE pr.[User] END) as [User],
IsNull(pr.BudgetedHours, 0.0),
IsNull(Sum(te.ActualHours), 0.0)
FROM Project p
LEFT JOIN ProjectResources pr on p.ProjectId = pr.ProjectId
LEFT JOIN TimeSheetEntries te on p.p.ProjectId = te.ProjectId
GROUP BY p.ProjectId, te.User, pr.BudgetedHours
但我对你的外地名称等进行猜测。 因此,你们需要为自己的领域进行调整。
我认为,你之所以存在问题,是因为你想到的是,实际时间和预算时间基本上平等,因为他们被分配到该项目中。
然而,实际和预算的计算方式非常不同。 如以下例子所示,你需要使用单独的子类计算:
select coalesce(budget.ProjectId, actual.ProjectId) as ProjectId,
budget.BudgetedHours, actual.ActualHours
from
(
select projectid, sum(pr.hours) as BudgetedHours
from Projects p
left outer join ProjectResources pr
) budget
full outer join
(
select projectid, sum(tse.hours) as ActualHours
from Projects p
left outer join TimeSheetEntries tse
on tse.ProjectId = p.ProjectId
) actual
on budget.ProjectId = actual.ProjectId
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