Question

以下算法增加了公司阵列的用户。我想为任何特定公司增加一个用户。我怎么去做。

public function all_company_information($id = null){
        $arrCompany = array();
        $arrCompany[ company ]= array();
        $arrData = array();
        $this->autoRender = false;
        $this->loadModel("User");
        $users = $this->User->find( all );
        foreach($users as $k => $user){


                if(!in_array($user[ User ][ company_id ], $arrCompany[ company ])){

                    $arrCompany[ company ][$user[ User ][ company_id ]][] = $user;

                }else{

                $arrCompany[ company ][$user[ User ][ company_id ]][] = $user;

                }

        }

    }

Answer 1

如果在公司模式上发现,那么你可以很容易地得到用户的计算。

$results = $this->Company->find( all );
foreach($results as $k => $company) {
    $results[$k][ Company ][ user_count ] = count($company[ User ]);
}

大致如此。返还结果将是一系列<代码>Company记录,每个<代码>Company记录都将在<代码>上列出相关用户记录清单。用户钥匙。

友情链接