Question

I want open a screen on host1 and change directory to $HOME/bin. host2 and change directory to $HOME/prj.

这里是我的手稿,但骑手可以工作。

#!/bin/bash

start_host() {
    screen ssh $1
    sleep 1
    screen -X chdir $2
}

[ x"$TERM" = x"screen" ] || exec screen -ln -S xxx -c /dev/null $0
sleep 1
screen -X zombie cr
screen -X caption always "%{= wk}%-w%{= BW}%n:%t%{-}%+w%-="

screen /bin/bash
start_host host1 bin
start_host host2 prj

Answer 1

我假定,你的问题是开始(在职能<代码>上)而不是按顺序进行筛选。这意味着指挥<条码> 屏幕扫描仪表1 封顶功能,执行过程可持续到<条码><>>>。

我建议使用<代码>-d-m,开始按脱节方式进行筛选:

start_host() {
  screen -d -m ssh $1
  sleep 1
  screen -X chdir $2
}

Answer 2

这里是我经过尝试和错误后的解决办法。

#!/bin/bash
start_host() { # <host> <dir>
  screen ssh $1
  screen -X eval "stuff  cd $2 " "stuff 15"
  screen -X select 0
}

[ x"$TERM" = x"screen" ] || exec screen -l -c /dev/null $0 $*
screen -X caption always "%{= wk}%-w%{= BW}%n:%t%{-}%+w%-="

start_host host1 bin
start_host host2 prj
read -p "Press enter to quit all windows" a
screen -X quit

友情链接