Question

我的法典是:

var obj = $( [id$=ddlInsert4] )
obj.disable = true;

ob倒了名单上,但令人沮丧的呼吁却使下一份名单失去意义。

alert(obj.val()) //this returns the correct value

Since my alert is returning the correct value, I know my jQuery syntax is correct. What am I missing?

Answer 1

obj is a jQuery Object, not a DOM content. 您需要填写$(obj).prop(残疾,真实);。更糟糕的是,如果您不需要obj。其它地方的变量是:

$( [id$=ddlInsert4] ).prop( disabled , true)

为了与本地的多功能部分进行交流,您可读到“密码>[0]>>>>(或“密码>.get(0)>。然后,你可以做到:

obj[0].disabled = true;

(表示该财产为disabled notdisable)

注:$[id$=dlInsert4] > 可返还多个要素,[0] 仅能收到第一个要素。如果他们不止一个,那么你们就应该 lo。我建议使用j Query .prop。但是,这种方法将取代你们的所有要素。

Answer 2

Try using .prop like below,

$( [id$=ddlInsert4] ).prop( disabled , true);

You can use jQuery .prop function like above

or

$( [id$=ddlInsert4] ) returns a jquery object (selector always returns array of jQuery object) so You cannot set DOM properties on jQuery object like that..

You need to iterate in a loop and set the property ex: $( [id$=ddlInsert4] )[i].disabled = true where i is the index.

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