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How can I upload files to a server using JSP/Servlet? (14 answers)

Closed 9 years ago.

如何在被装成多部分/格式数据时,在服务器中获取形式价值。

<FORM name="filesForm" action="FileUpload" method="post" enctype="multipart/form-data">
<input type="text" name="firstname">
<input type="text" name="lastname">
<input type="file" name="filename">
</form>

如何将这些价值观纳入“保护手册”第一名称、最后名称和档案价值。

Answer 1

http://commons.apache.org/fileupload/“rel=“nofollow” http://commons.apache.org/fileupload/。

总的来说,你的法典将探讨这样的问题:

import org.apache.commons.fileupload.*;

......

DiskFileUpload upload = new DiskFileUpload();
List<FileItem> items = upload.parseRequest(request); // request is HttpServletRequest

// iterate through form fields
for(FileItem item:items) {
    if(item.isFormField()) { // text fields, etc......
        String fieldName = item.getFieldName();
        String value = item.getString();
    } else { // file fields
        item.write(new File("some/path"));
    }
}

友情链接