Question

我完全听了UIScrollView,以显示我的形象,其中使用了一些摄影师的密码。 a pple样本代码。我很少混淆一谈,一看一字的图像,一看是轮流的。任何帮助都将受到赞赏。

NS Carlo in calls willRotate ToInterfaceOrientation:duration:

2012-05-12 11:35:45.666 imageScrollView frame X and Y are 0.000000 and 0.000000 
2012-05-12 11:35:45.672 imageScrollView frame Width and Height are 320.000000 and 480.000000 
2012-05-12 11:35:45.677 imageScrollView bounds origin X and Y are 0.000000 and 0.000000 
2012-05-12 11:35:45.682 imageScrollView bounds Width and Height are 320.000000 and 480.000000 
2012-05-12 11:35:45.686 imageView frame origin X and Y are 0.000005 and 0.374437
2012-05-12 11:35:45.689 imageView frame size Width and Height are 320.000000 and 479.251129
2012-05-12 11:35:45.693 imageView bounds origin X and Y are 0.000000 and 0.000000
2012-05-12 11:35:45.697 imageView bounds size Width and Height are 641.000000 and 959.999939
2012-05-12 11:35:45.701 boundsCenter X and Y are 160.000000 and 240.000000 
2012-05-12 11:35:45.705 convertPoint origin X and Y are 320.500000 and 479.999969

NS Carlo in calls willAnimateRotation ToInterfaceOrientation:duration:

2012-05-12 11:36:05.975 imageScrollView frame X and Y are 0.000000 and 0.000000 
2012-05-12 11:36:05.978 imageScrollView frame Width and Height are 480.000000 and 320.000000 
2012-05-12 11:36:05.983 imageScrollView bounds origin X and Y are 0.000000 and 0.000000 
2012-05-12 11:36:05.987 imageScrollView bounds Width and Height are 480.000000 and 320.000000 
2012-05-12 11:36:05.990 imageView frame origin X and Y are 80.000008 and 0.000017
//I am confused here. Why is the X is 80.000008, and Y is 0.000017, but not (80, -120)?
2012-05-12 11:36:05.994 imageView frame size Width and Height are 320.000000 and 479.251099
2012-05-12 11:36:06.002 imageView bounds origin X and Y are 0.000000 and 0.000000
2012-05-12 11:36:06.006 imageView bounds size Width and Height are 641.000000 and 959.999878
2012-05-12 11:36:06.009 boundsCenter X and Y are 240.000000 and 160.000000 
2012-05-12 11:36:06.014 convertPoint origin X and Y are 320.500000 and 320.499969

www.un.org/spanish/ecosoc 关于自动化配置:

actionSheetCoverView.autoresizingMask = UIViewAutoresizingFlexibleHeight | UIViewAutoresizingFlexibleWidth;
imageScrollView.autoresizingMask = UIViewAutoresizingFlexibleHeight | UIViewAutoresizingFlexibleWidth;
imageView.autoresizingMask = UIViewAutoresizingFlexibleTopMargin | UIViewAutoresizingFlexibleBottomMargin | UIViewAutoresizingFlexibleLeftMargin | UIViewAutoresizingFlexibleRightMargin;

www.un.org/spanish/ecosoc 之前的图像调查框架(国家测验记录仪中将外向定位:持续时间)是(0,0)轮值之后的(国家测验仪表显示:持续时间),即(80,120)。但它是(80.008,0.000017);。

Answer 1

。

参看http://developer.apple.com/library/ios/#documentation/uikit/fer/uiview_class/UIView/UIView.html#/apple_ref/doc/uid/TP40006816-CH3-SW5” rel=“nofollow noreferer” UIViewdocument:

如果<代码>transform property is not the identity transformation,则frame property的价值不明确,因此应予忽视。

问题是,在轮值开始时,你重新读到<条码>><>>>财产,这意味着你的意见将具有一种不明确性<条码>。数值,使其<条码>范围值失去意义。

您可根据您的“上登出这样的变值:

NSLog(@"imageScrollView transform %@", NSStringFromCGAffineTransform(self.transform));

NSLog(@"imageView transform %@", NSStringFromCGAffineTransform(imageView.transform));

This will show you the transform property at the time of rotation. If you re not familiar with the Identity Transform, it s [1, 0, 0, 1, 0, 0].

换言之,<条码>>范围<> /代码>的财产给你意料想的价值,因为您的观点是:<条码>transform适用于该代码,使<条码>>>财产失去意义。

这并不明确你实际上想要达到的目标,但同一 Apple果文件的其他说明可能有助于:

如果<代码>transform property includes a non-identity transformation,则frame property的价值不明确,不应修改。在这种情况下,你可以改用<代码>center 财产,并改用 已限/代码>的财产来调整规模。

Answer 2

正如我所解释的那样,当你不说你被混淆或你试图做什么时,很难帮助你。

为了获得图像观测的实际中心,你可以使用:

imageView.center

友情链接