Question

我有以下表格:

var markers = [
    [ Title , 15.102253, 38.0505243,  Description , 1], 
    [ Another Title , 15.102253, 38.0505243,  Another Description , 2],
    [ Title 3 , 15.102253, 38.0505243,  Description 3 , 3], 
];

接着,我收到一个把 com子分开的问讯(m=1,2),以建立如下阵列:

[ 1 ,  2 ]

What I need to do is find all markers where the ID (markers[i][4]) comes from the query string.

实现这一目标的最佳途径是什么? 理想的情况是,我只想像标记那样,以同样的格式建立第3个阵列,但只显示点击的结果。

Any help would be greatly appreciated.

成就

Answer 1

一种选择是使用nes:

var markers = [
    [ Title , 15.102253, 38.0505243,  Description , 1], 
    [ Another Title , 15.102253, 38.0505243,  Another Description , 2],
    [ Title 3 , 15.102253, 38.0505243,  Description 3 , 3], 
];
var search = [ 1 ,  2 ];
var result = [];

for (var i = 0; i < search.length; i++)
    for (var j = 0; j < markers.length; j++)
        if (search[i] == markers[j][4]) {
            result.push(markers[j]);
            break;
        }

console.log(result);

http://jsfiddle.net/3TErD/“rel=“nofollow” http://jsfiddle.net/3TErD/。

Answer 2

Couldn t you just use a nested loop here?

var filteredMarkers = [];

for(var i = 0; i < markers.length; i++) {

    for(var j = 0; j < queryStringArray.length; j++) {

        // this might need to be changed as your markers has index 4 as a number whereas the queryString array appears to be strings.
        if(markers[i][4] === queryStringArray[j]) {

            filteredMarkers.push(markers[i]);
            break;

        }

    }

}

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