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尽管我们提交了阵列,但还是发出警告
原标题:usort() warning although submitting array

为什么有“<代码>>sort()”的阵列?

if ( is_array( $tables ) ) {
    usort( $tables,  sort  );
} else {
    echo "no array";
}

我总是得到这一警告:

(a) 估计参数1为阵列,显示

因此,php认为其阵列,但usort(不是

heres the sort function:

function sort( $a, $b ) {
    return strlen( $b ) - strlen( $a );
}
最佳回答

注:错误如下:sort() 预期,而不是usort() 预期。 这是因为,PHP正在将电话传译为usort,作为内装的:sort(方法(预计1参数为阵列),而不是方法)。

请将贵方法重新命名为其他办法,如my_sort

function my_sort( $a, $b ) {
    return strlen( $b ) - strlen( $a );
}

if ( is_array( $tables ) ) {
    usort( $tables,  my_sort  );
} else {
    echo "no array";
}
问题回答

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