我需要找到一个针头出现在灰色中的几倍。 直到这一点为止,我制定了以下法典:
<?php
$haystack = http://www.google.com ;
$needle = a ;
$contents = file_get_contents($haystack);
?>
我想找到一个(针头)的次数出现在元件中(沙斯特法克-古里戈.com源代码)。
谢谢。
我需要找到一个针头出现在灰色中的几倍。 直到这一点为止,我制定了以下法典:
<?php
$haystack = http://www.google.com ;
$needle = a ;
$contents = file_get_contents($haystack);
?>
我想找到一个(针头)的次数出现在元件中(沙斯特法克-古里戈.com源代码)。
谢谢。
substr_count
这正是你所期待的。
needle = sses
haystack = assesses
count = 0
if needle in haystack:
index = haystack.index(needle)
string1 = haystack[index:len(needle) + index]
for position in range(0,len(haystack)):
if haystack[position:len(needle) + position] == string1:
count += 1
print (count)
......产出为2。
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