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保持排位,直到在java提供投入为止。
原标题:Keep Looping until inputs are available in java

如果我不知道投入的规模已经存在,那么,在阿加瓦邦,究竟是怎样才能保持循环。 在C++中,可以做如下工作。

int main(){
    int val;
    while(cin >> val){
           //do stuff
    } 
}

在java做类似事情的方法是什么。

Thanks in Advance. Shantanu

最佳回答

你们应当尝试以下事情。

    long val;
    Scanner sc = new Scanner(System.in).useDelimiter("
");
    while (sc.hasNext()) {
        String temp = sc.next().trim();

        val = Long.parseLong(temp);
        // do stuff
    }
问题回答

一种办法是使用斯堪纳语。

long val;
Scanner sc=new Scanner(System.in);
while (sc.hasNextLong() ) {
    val = sc.nextLong();
    // do stuff
}

这相当于你提供的电压法。 但并不是你要求什么。 只要有法律投入可读体。

根据你的具体要求,采用斯堪的班级的方法。 这句话是一行。 哪一种意味着用户必须进入多数系统。

public static void main(String[] args)
{
    String str=new Scanner(System.in).nextLine();
}

不要实施公共汽车。 你可能更喜欢使用溪流。 在数据到来之前,代号(<)被阻断,因此,你的代码将简明扼要,不像你所希望的那样,不忙 lo和工作:

while ( in.read() != -1) {
   // do your stuff
}

or even better using buffers:

byte[] buf = new buf[MAX_SIZE]
while ( in.read(buf) != -1) {
   // do your stuff
}

i. 相信服务于您目的的最佳途径是,通过多面阅读,一面透镜将等待用户的投入,再让用户知道何时收到。 在时间上,另一个路面将保持循环。





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