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原标题:Copy number of bytes to a position in memory
  • 时间:2012-05-15 23:18:41
  •  标签:
  • c++

If I am not correct, the codes following are used to copy an array of bytes to a position of memory in C#:

byte[] byteName = Encoding.ASCII.GetBytes("Hello There");

int positionMemory = getPosition();

Marshal.Copy(byteName, 0, new IntPtr(positionMemory), byteName.length);

我如何在本土C++中做到这一点?

最佳回答

使用点子和薄膜:

void * memcpy ( void * destination, const void * source, size_t num );

附录一

memcpy (B, A, n * sizeof(char));

这比C++更是C++,护卫班拥有你可以使用的复印能力。

  size_t length;
  char buffer[20];
  string str ("Test string...");
  length=str.copy(buffer,6,5);
  buffer[length]=  ;

这里有一个比较具体的例子,有一部完整法典:

#include <stdio.h>
#include <string>
#include <string.h>
#include <iostream>

using namespace std;
int main()
{

    string s("Hello World");
    char buffer [255];
    void * p = buffer; // Or void * p = getPosition()
    memcpy(p,s.c_str(),s.length()+1);
    cout << s << endl;
    cout << buffer << endl;
    return 0;
}

让我知道,你们是否需要更多的细节?

问题回答

memcpy(),memmove(,CopyMemory( >,MoveMemory(> > 均可作为Marshal.Copy(>>的本地equi。 关于职位处理问题,所有职位都有。 NET代码正在把 in化成点,你也可以在C++中这样做。 您所显示的“网络”编码与下列内容相当:

std::string byteName = "Hello There"; 
int positionMemory = getPosition(); 
memcpy(reinterpret_cast<void*>(positionMemory), byteName.c_str(), byteName.length()); 




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