如果我有两个实体类别,即:Group
和Person
,如果在group
和Person
之间有一对一的关系(即,一个人可以属于多数集团,一个群体可以有许多人),那么,那么,我可以选择所有<密码>。 姓名/代码
Something like the reverse of select p from Group g inner join g.people p
...
如果我有两个实体类别,即:Group
和Person
,如果在group
和Person
之间有一对一的关系(即,一个人可以属于多数集团,一个群体可以有许多人),那么,那么,我可以选择所有<密码>。 姓名/代码
Something like the reverse of select p from Group g inner join g.people p
...
这项工作:
select p from Person p where p not in (select pg from Group g inner join g.persons pg)
或许:
select p from Person p where not exists (select 1 from Group g where p member of g.persons)
效率更高?
不管怎样,......欢迎对哪些方面更有效率的意见,但因为这两个“工作”都把问题列为回答。
If you want to have all persons who are not in a given group g, it should be like
from Person p where p.group.id != :gid;
并且,你给特定群体的补贴。
如果你想要所有没有团体的人,
from Person p where p.group.id is null;
如果你想让所有没有群体的人都到别处,但外国关键人物有可能拥有一个不属于任何集团但不属于现有集团的群体的群体的群体的群体(例如,如果该群体被删除而没有将这些人删除,也没有将他们转移到另一个群体)
from Person p where not exist (select 1 from Group g where g.id = p.group.id);
P. S. 我的发言是代表总部,但对于联合人民党来说,发言应大致相同。
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