Question

public class LockAppActivity extends Activity{

    EditText pass1, pass2;
    Button back, next;
    SharedPreferences prefs;

    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.lockapp);

        pass1 = (EditText) findViewById(R.id.edit1);
        pass2 = (EditText) findViewById(R.id.edit2);

        back = (Button) findViewById(R.id.back);
        back.setOnClickListener(new View.OnClickListener() {    
            public void onClick(View v1) {
                Intent setIntent = new Intent(Intent.ACTION_MAIN);
                setIntent.addCategory(Intent.CATEGORY_HOME);
                setIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
                startActivity(setIntent); 
            }
        });

        next = (Button) findViewById(R.id.next);
        next.setOnClickListener(new View.OnClickListener() {
            String password1 = "";
            String password2 = "";

            public void onClick(View v){

                password1 = pass1.getText().toString();
                password2 = pass2.getText().toString();             

                if (!password1.equals("")){

                    if (password1.length() >= 15){
                        Pattern pattern = Pattern.compile("[[0-9]&&[a-z]&&[A-Z]]");
                        Matcher matcher = pattern.matcher(password1);   

                        if(matcher.matches()){                      

                            if (password1.equals(password2)){
                                //SavePreferences("Password", password1);
                                Intent intent = new Intent(LockAppActivity.this, PhoneNumActivity.class);
                                startActivity(intent);
                            }
                            else{
                                pass1.setText("");
                                pass2.setText("");
                                Toast.makeText(LockAppActivity.this,"Not equal",Toast.LENGTH_LONG).show();
                            }
                        }
                        else{
                            pass1.setText("");
                            pass2.setText("");
                            Toast.makeText(LockAppActivity.this,"Not matched",Toast.LENGTH_LONG).show();
                        }
                    }
                    else{
                        pass1.setText("");
                        pass2.setText("");
                        Toast.makeText(LockAppActivity.this,"Length",Toast.LENGTH_LONG).show();
                    }                       
                }
                else{
                    pass1.setText("");
                    pass2.setText("");
                    Toast.makeText(LockAppActivity.this,"Nothing",Toast.LENGTH_LONG).show();
                }
            }
        });
    }

    private void SavePreferences(String key, String value){
        SharedPreferences sharedPreferences = getPreferences(MODE_PRIVATE);
        SharedPreferences.Editor editor = sharedPreferences.edit();
        editor.putString(key, value);
        editor.commit();
    }
}

我在进入有效密码时面临问题,但是,我pop着一位名叫“不匹配”的传闻,以及我如何在口中挽救这一密码,而新密码进入时,会更新和推翻旧密码。

Answer 1

在Java regex flavor,&&是一个固定的交叉运营商。它只使用内部品级。阁下:

[[0-9]&&[a-z]&&[A-Z]]

......力求使一种特性相匹配,该特性必须成为所有三套代码([0-9]、[A-Z]和[a-z]的成员。显然不存在这种性质。验证密码的最常见办法是使用单独的头盔,与每种所需特性类型相匹配,然后进行“实际”匹配,以验证长度和整体构成。在你看来,它可能这样做:

^(?=.*[0-9])(?=.*[A-Z])(?=.*[a-z])[0-9A-Za-z]{15,}$

您重新使用<代码>matches()方法应用该证书,因此您实际上不必使用起始和终点站(^/code>和_$),但并未造成任何伤害,并且更明确地将你的意图告知必须读到你的代码后的人。



请注意,我只更正你的格格外,以符合你申明的标准,而不评论标准本身。 如果在《守则》的特定部分存在任何错误,我不知道。

Answer 2

You can validate the Password using Regualar Expression as below

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class PasswordValidator{

  private Pattern pattern;
  private Matcher matcher;

  private static final String PASSWORD_PATTERN = 
          "((?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[@#$%]).{6,20})";

  public PasswordValidator(){
      pattern = Pattern.compile(PASSWORD_PATTERN);
  }

  /**
   * Validate password with regular expression
   * @param password password for validation
   * @return true valid password, false invalid password
   */
  public boolean validate(final String password){

      matcher = pattern.matcher(password);
      return matcher.matches();

  }
}

更多参考:

友情链接