Question

我如何能够得到以下数字的总和? 在加入之前,他们正在倍增。

Input File (count.txt)
2*4
2*1
3*1
3*1
2*1
2*1

Command I am using:
( echo 0 ; sed  s/$/ +/  count.txt; echo p ) | dc.

The Sum I am getting is 343 which is not correct. I am expecting 20 as sum.

2*4
2*1
3*1
3*1
2*1
2*1

概述:20(每行一次复制,然后是总和)

任何想法?

Thanks, Raj

Answer 1

还将完成以下工作:

awk -F *   {i+=$1*$2} END{print i}  count.txt

Answer 2

这项工作应当:

cat count.txt | tr \n + | sed  s/$/
/  | bc

否则,你必须修改原封不动的表述。

Answer 3

cat count | while read line; do echo $(($line)); done | awk  {i+=$1} END {print i}

This is the best solution I could come up with, hope it helps.