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无法在实验室变量中增加阵列:
原标题:Not able to add a string to array from a variable in php:

我是新到的。 我一直在努力在营地建造一个阵列,并将其编码给JSON。 用户方面将使用<条码>xml<>查询>/代码>接收。

但有问题。 我无法书写阵列的一个变量。

这是我试图做的事。

$name=$_GET[ username ];
if ( strcmp( $name,  harry  ) ) {
  $arr[ status ] =  success ;
  $arr[ name ] = $name;
  echo json_encode($arr);
}

但当我向客户提出要求时。 我拿不出任何价值取代变量。 除这一价值外,阵列中的其他一切都属于罚款。

对应案文

{"status":"success","username":null}

我在分配价值方面做了一些错误?

谢谢。

问题回答

在你再次向客户方寄送的阵列中,没有用户名钥匙,相反,你应当使用美元。

我不知道在这种情形下使用斯特伦的好处,但这将纠正你的问题。

if ( strcmp( $name,  harry  ) === 0) {

此处使用方言是一种旁观,因此,你可以使用方言。

if ( $name ===  harry  ) {

遵循我守则...... 检查

$name=$_GET[ username ];
if(strcmp($name, harry )==0)
{
$arr[ status ]=  success ;
$arr[ name ]=$name;
echo json_encode($arr);
}
$name=$_GET[ username ];
if ( strcmp( $name,  harry  )===0 ) {
  $arr[ status ] =  success ;
  $arr[ username ] = $name; <---------- changed the index in $arr from  name  to  username 
  echo json_encode($arr);
}





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