Question

I have an HTML form. When visitor submits form, a javascript method is invoked. This method sends an AJAX request to my server s php file. My problem is i need to get the visitor s ip address. But because of AJAX request calls php file, $_SERVER[ REMOTE_ADDR ] gives me my server s address. How can i get visitor s ip, in this case? Thank you

<form onsubmit="sendData(); return false;">
    // some data here
</form>

function sendData(){
    // do some work, get variables
    $.ajax({
        url:"/mypage.php",
        type:"GET",
        data: { name: e },
        success : function(data) {
           // do some work
        },
        error: function (xhr, ajaxOptions, thrownError) {
        }
    })
}

// in mypage.php
public function useData() {
        $name=$_GET["name"];
        $ip = $_SERVER[ REMOTE_ADDR ];
}

Answer 1

<代码>_SERVER[REMOTE_ADDR]将给您客户的IP地址。但是,由于你大概使用服务器和<>/strong>客户的同一机器,你获得的也是正常的。一旦你将网站作为网络服务器,并且从不同的机器中远程访问,你将获得该遥远机器的地址。

因此,你无需做些什么。你的法典已经按照预期发挥作用。

Answer 2

jax要求仍然来自客户,应当给予客户IP而不是服务器。

Answer 3

通过以下方式尝试守则,因为它意在上载上该页,它使用舱位和一些免费的皮页。

$(document).ready(function(){
  $.getJSON("https://api.ipify.org?format=json", function(data){
    var userIP = data.ip;
    $.getJSON("https://api.ipgeolocationapi.com/geolocate/" + userIP, function(data){
      var userLat = data.geo.latitude;
      var userLng = data.geo.longitude;
      // You can now use the user s latitude and longitude to determine if they re within your geo fence
    });
  });
});

友情链接