Question

我有以下法典:

NSUserDefaults *userDefaults = [NSUserDefaults standardUserDefaults];
NSMutableDictionary *golferIconsu = [userDefaults objectForKey:@"golferIconsFirstScene"];

NSMutableDictionary *golferIconsSceneOne = [[NSMutableDictionary alloc]initWithDictionary:golferIconsu];

NSMutableDictionary *savedScoreCards;

NSMutableDictionary *currentScoreCard;
[currentScoreCard setObject:golferIconsSceneOne forKey:@"golferIconsFirstScene"];

NSMutableDictionary *GI = [currentScoreCard objectForKey:@"golferIconsFirstScene"];

[savedScoreCards setObject:currentScoreCard forKey:@"1"];

NSLog([golferIconsSceneOne objectForKey:@"30101"]);
NSLog([GI objectForKey:@"30101"]);

归根结底,在我的记录中印发的都是第1条<编码>NS Carlo电话,而不是第2条。例如:

NSLog([golferIconsSceneOne objectForKey:@"30101"]);

这部印刷了我存放在该字典上的插图。

This one:

NSLog([GI objectForKey:@"30101"]);

根本没有印刷任何东西。

如何获得<代码>NSDictionary GI拥有与golferIconsScene One完全相同的特性,但我需要利用的目前核心标准<<0>代码>,其中载有golferIconsScene One/code>?

Answer 1

1. 在提出反对之前先提出字句。

NSMutableDictionary *savedScoreCards = [[NSMutableDictionary alloc] init];
NSMutableDictionary *currentScoreCard = [[NSMutableDictionary alloc] init];

Answer 2

Do like this intialize one and set it into other

NSMutableDictionary *savedScoreCards = [[NSMutableDictionary alloc] init];
NSMutableDictionary *currentScoreCard = [[NSMutableDictionary dictionaryWithDictionary:savedScoreCards];

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