Question

我有以下接口:

template <class T>
class AbstractTask {
public:
    virtual void BindTaskCompleted(AbstractTask<T> &bindedTask)=0;
    virtual void Join(TaskResult<T>)=0;
};

并且:

template <class T>
class SlaveTask: public AbstractTask<T> {
public:
    typedef boost::function<void(TaskResult<T>)> joinFunction;

    void BindTaskCompleted(AbstractTask<T> &bindedTask)
    {
        /////////////WORK OK//////////////////////////////  
        //bindedTask.Join(result);

        /////////////COMPILATION ERROR/////////////////////
        slaveTaskCompletionFunction=boost::bind(&AbstractTask<T>::Join,bindedTask,result);
    }

     void Join(TaskResult<T> r)
    {
        slaveTaskCompletionFunction(r);
    }

private:
    joinFunction slaveTaskCompletionFunction;
    TaskResult<T> result;

};

I m试图将执行摘要Task的虚拟Join方法学捆绑起来,以促进:与同一签名相操作。助推:Bbind投掷了77个汇编错误,我看不出原因。

I thought at first that boost::bind couldn t be use with virtual method but this doesn t seem to be the case: Virtual function and boost bind strange behavior

事先感谢你们的帮助!

Thomas

Answer 1

问题是,你把所有论点都束缚在后面,但<条码>boost:功能,以及你如何重新使用条码表示它想有1个论点。

修改如下。

slaveTaskCompletionFunction=boost:bind(&AbstractTask<T>:Join,&bindedTask,_1);

Edit: Also, you had a slicing problem when you passed in bindedTask by reference. You either have to pass it in by pointer, or use boost::ref; otherwise, boost::bind attempts to make a copy of the AbstractTask<T>, and will end up only copying the interface.

Answer 2

要求:

slaveTaskCompletionFunction=boost::bind(&AbstractTask<T>::Join, &bindedTask, _1);

Answer 3

无论是否受到约束任务:

   BindTaskCompleted(const AbstractTask<T> &bindedTask)

or use boost::ref to bind it:

   boost::bind(&AbstractTask<T>::Join,boost::ref(bindedTask),result);

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