能否绕过Java API关系所赋予的财产所命令的节点?
Source node *--- 4 ---> * Node 1
|
+--- 3 ---> * Node 2
|
+--- 2 ---> * Node 3
|
--- 1 ---> * Node 4
Where * s are nodes and the numbers between - s are relation properties. Such that the above would give the nodes 4, 3, 2 and 1.
那样的话,你必须先找到所有这些关系,然后对它们进行分类。如果你在十字路口使用这些关系,那么这种行为就可以在“情感探索者”中被编码。
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