我已经有了一个 < code> victor< MyType> , 想要另一个 < code> victor & lt; myType> , 仅包含满足某些简单标准的 MyTypes, 例如, 某些数据成员等于某东西。 解决问题的最佳方法是什么?
使用 opy_if :
#include <algorithm> // for copy_if
#include <iterator> // for back_inserter
std::vector<MyType> v2;
std::copy_if(v1.begin(), v1.end(), std::back_inserter(v2),
[](MyType const & x) { return simple_citerion(x); } );
使用一点点的靴子,你可以:
std::vector<int> v = {1,2,-9,3};
for (auto i : v | filtered(_arg1 >=0))
std::cout << i << "
";
此样本对表达式模板(
更多展示材料和完整的例子请见此 :
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