我写了这个代码,它的工作原理, 但我仍然在想,是否有任何其他解决方案 更好,更简单。
$sql = "select * from db_member where username = $name ";
$result = mysql_query($sql) or error(mysql_error());
if(mysql_num_rows($result) < 1)
{
error("There is no user with name $name .");
}
我写了这个代码,它的工作原理, 但我仍然在想,是否有任何其他解决方案 更好,更简单。
$sql = "select * from db_member where username = $name ";
$result = mysql_query($sql) or error(mysql_error());
if(mysql_num_rows($result) < 1)
{
error("There is no user with name $name .");
}
一个更快的方法来做到这一点:
$result = mysql_query("SELECT COUNT(1) FROM db_member WHERE username= ".mysql_real_escape_string($name)." ") or die(mysql_error());
if (mysql_result($result, 0) == 0) {
echo There is no user with name . htmlspecialchars($name, ENT_QUOTES, UTF-8 ) . . ;
}
请检查 < a href=> "http://php.net/pdo" rel="nofollow" >http://php.net/pdo , 以更好地处理错误和查询参数....
我想这样用我的口吻... 已经不行了...
不,如果没有其他细节,这是一个很好的解决办法。然而,你可以看一下以下各点:
参考参考值
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