Question

我用日蚀来解冻[ p p a Android app. 应用程序将用户名和密码发送到php (服务器侧面), 如果用户不存在, 它返回“ 未找到 ” 。

现在我不想使用json:-)

我的问题是, 我无法做EQQQUAL 重弦!!!!!

if(text=="not found") ShowMessage("Invalid user and password !!");

或

if(text==getResources().getString(R.string.wronguser))
    ShowMessage("Invalid user and password !!");

我尝试了... 等(..) 函数,但它不是工作...

当我把回信卷指派给文本视图时,它显示我“找不到”,所以为什么 = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = =

我的php使用 UTF-8 编码... THANX:-)

Answer 1

在 Java 字符串中,应使用 . 等同 比较。 ( 进行身份比较,而 . 等同比较实际内容。 )



所以从改变开始

if (text=="not found") ...


至

if (text.equals("not found")) ...


等

If that doesn t seem 至 work, make sure the strings doesn t contain unexpected leading / trailing white-space. You may also want 至 ignore case:

if (text.trim().equalsIgnoreCase("not found")) ...

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