我有一张叫做行程表的表格,上面有港口、进港和出港等清单。
日字段显示行程的天数 1,2,3 等
表格是这样的
身份、 日、 日、 订单、 港口、 端口_ id、 类型、 抵达、 出发、 巡航_ id
我想选择每个记录, 如果巡航日志有超过一天一站以上, 这样我就可以更新命令字段, 这样当日的站点会按正确的顺序列出...
例如:
25号巡航船有第3天的2个行程记录
我只想选择这些记录,然后我就可以进行更新查询,但我正努力要正确选择它们
我想我完全偏离了轨道 与这个...
SELECT * , COUNT( DAY ) FROM itinerary GROUP BY cruise_id LIMIT 0 , 30
使用 HAVING 和 GROUP by 。 这应该是:
SELECT *, COUNT(id) AS c
FROM itinerary
GROUP BY cruise_id, day
HAVING c > 1
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