Question

在 Java 中, 我试图分割 < code_ / code> 字符, 但它无法识别。解开 < code_ / code > 丢弃代码错误。

这是个特殊人物还是我需要做点别的事才能让它认出来?

String splitChr = "^";
String[] fmgStrng = aryToSplit.split(splitChr);

Answer 1

在 Java regex 中是一个特殊字符, 意思是“ 匹配输入的起始点 ” 。



You will need to escape it with "\^". The double slash is needed to escape the , otherwise Java s compiler will think you re attempting to use a special ^ sequence in a string, similar to 
 for newlines.

 不是一个特殊的逃生序列, 因此您会收到编译错误 。


简言之,请使用 \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\

Answer 2

\\\ 匹配字符串的起始点。您需要逃离它, 但在这种情况下您需要逃离它, 这样正则表达式解析器就能理解它意味着逃离, 所以 :

String splitChr = "\^";
...

应该让你得到你想要的。

Answer 3

String.split () 接受一个regex。符号是一个特殊符号,用来标明输入序列的起始点。您需要避开它才能使输入序列发挥作用。您用试图避开它是正确的, 但是它是一个特殊字符, 用来在 Java 字符串中逃避事物, 所以您需要用另一个来逃避逃跑字符。它会给您提供 :

\^

Answer 4

使用 \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\可以\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\



    String aryToSplit = "word1^word2";
    String splitChr = "\^";
    String[] fmgStrng = aryToSplit.split(splitChr); 
    System.out.println(fmgStrng[0]+","+fmgStrng[1]);


It should print "word1,word2", effectively splitting the string using "\^". The first slash is used to escape the second slash. If there were no double slash, Java would think ^ was an escape character, like the newline "
"

Answer 5

上述任何答案都没有意义,这是正确的解释。

As we all know, ^ doesn t need to be escaped in Java String.
As ^ is special charectar in RegulalExpression , it expects you to pass in ^
How do we make string ^ in java? Like this String splitstr = "\^";

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