Question

问题在于代码 < / strong> 中的评论,

简单问题, 但我似乎找不到一个答案。我想将字符串转换为 s byte [] (easy, String.getBytes () ) 。然后我想将字节的字符串( 1011011010101010001 等)转换为字节 [], 并获得字节的字符串值( 也很简单 : new String(byte) )

这是我到现在为止得到的:

Scanner scan = new Scanner(System.in);
String string = scan.nextLine();
String byteString = "";
for (byte b : string.getBytes()) {
  byteString += b;
}
System.out.println(byteString);

//This isn t exactly how it works, these two parts in separate methods, but you get the idea...

String byteString = scan.nextLine();
byte[] bytes = byteString.literalToBytes() //<== or something like that...
//The line above is pretty much all I need...
String string = new String(bytes);
System.out.println(string);

Answer 1

好吧,因为>谁 (导致我 < a href="https://stackoverflow.com/a/205713/97592>这个答案 < a/a>)

Scanner scan = new Scanner(System.in);
String pass = scan.nextLine();
StringBuilder byteString = new StringBuilder();
for (byte b : pass.getBytes()) {
  b = (byte) (b);
  byteString.append(b).append(","); //appending that comma is what does the trick.
}
System.out.println(byteString);
//
String[] split = byteString.toString().split(","); //splitting by that comma is what does the trick... too...
byte[] bytes = new byte[split.length];
for (int i = 0; i < split.length; i++) {
  bytes[i] = (byte) (Byte.valueOf(split[i]).byteValue());
}
System.out.println(new String(bytes));

Answer 2

这将无法工作。问题在于当您将字节转换为字符串时, 您将会得到像字符串一样的字符串

25 32611134

分析一下这个字符串,是第一个字节 2,25,253,还是253?

唯一能完成这项工作的方法就是使用一个十进制格式,确保每个字节都是3个字符,字符串里有3个字符长

Answer 3

<强 > EDIT

请见解答。

有了这个,你可以:

String string = scan.nextLine();
String convertByte = convertByte(string.getBytes());
System.out.println(convertByte);
String byteString = scan.nextLine();
System.out.println(new String(convertStr(byteString)));

Answer 4

我猜你想要的是这个

// to get back the string from byte array
StringBuilder byteString = new StringBuilder();
for (byte b : string.getBytes()) {
    byteString.append((char)b);
}
   System.out.println(byteString.toString());
// to get the binary representation from string
StringBuilder byteString = new StringBuilder();
    for (byte b : string.getBytes()) {
        System.out.print(Integer.toBinaryString((int)b));
    }
        System.out.println(byteString.toString());

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