我有一个目标,就叫它吧
class Foo {
String greeting = "Hello";
int age = 21;
}
我要转换为地图, 如 "greeting" {gt; "Hello," "age" {gt; 21
。 这将在 JsonSregier.toJSON(arg)
中用作参数
Perl 和 Python 等语言非常擅长这种交流。 在爪哇,什么是一个很好的实践方法?
我有一个目标,就叫它吧
class Foo {
String greeting = "Hello";
int age = 21;
}
我要转换为地图, 如 "greeting" {gt; "Hello," "age" {gt; 21
。 这将在 JsonSregier.toJSON(arg)
中用作参数
Perl 和 Python 等语言非常擅长这种交流。 在爪哇,什么是一个很好的实践方法?
您不需要在序列化之前进行此转换 。
Gson会直接用你的东西 把它做成JSON地图
使用此选项, 例如 :
Gson gson = new GsonBuilder().create();
writer.write(gson.toJson(foo)); // foo is an instance of Foo
您可以直接使用 < a href=> "http://jackson.codehaus.org//" rel="no follow" > Jackson 来连环POJOs。 工作非常成功 。
import java.io.Writer;
import java.io.StringWriter;
import org.codehaus.jackson.map.ObjectMapper;
Foo foo = new MyFoo("hello", 21);
ObjectMapper mapper = new ObjectMapper();
Writer writer= new StringWriter();
mapper.writeValue(writer, foo);
String json = writer.toString();
System.out.println(json);
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