Question

我需要在 Java 使用 split () 方法分割组装代码行。以下为样本代码 :

String line = "Add a, b, c";
String[] parts = line.split("[\s+,]");
System.out.println(Arrays.toString(parts));

<强>UUTPUT:

[Add, a, , b, c]

我需要输出像:

[Add, a, b, c]

用于下列任何一种投入:

String line = "Add a,b,c";
String line = "Add   a  ,b,c";
String line = "Add a,  b,c";
String line = "Add a,b , c";
String line = "Add a , b , c";

或任何类似案件。

取代 [\\s+] 的权利是什么?

Answer 1

应采取下列行动:

String[] parts = line.split("[\s,]+");

您当前的正反方正匹配一个空格, 或完全匹配一个 , 或完全匹配一个逗号。

上述正方形符合一个或多个空格和/或逗号。

区别在于 的位置:当它出现在字符类中时,它被直截了当地解释。

Answer 2

[\\]\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\

Answer 3

尝试一些大致如下的尝试:

Add? ([0-9]+)?,?,([0-9]+)?,?,([0-9]+)??"

"[Add 1, 2, 3]"

([0-9]+) should let it take any sized number

_? should make room for an optional space

1 should backreference to the value first found by the first set of ()

2 " " " " " " " second set of ()

3 " " " " " " " third set of ()

The logic is sound but make sure my syntax is correct.

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