Question

我试图解析一个 XML, 并将 URL 从 XML 的一个元素存储到一个 NSArray 。这是我目前为止的代码 :

 NSURL *url = [NSURL URLWithString:@"http://www.316apps.com/LakesideDocs/podcasttrial.xml"];

   NSData *xmlData = [[NSMutableData alloc] initWithContentsOfURL:url];
   NSError *error;
   GDataXMLDocument *doc = [[GDataXMLDocument alloc] initWithData:xmlData 
                                                          options:0 error:&error];

   NSArray *channels = [doc.rootElement elementsForName:@"channel"];
   for (GDataXMLElement *channel in channels) {            


       NSArray *items = [channel elementsForName:@"item"];
       for (GDataXMLElement *item in items) {

           NSString *articlePoint = [item valueForChild:@"link"];
           NSArray *linkarray = [[NSArray alloc] initWithObjects:articlePoint, nil];

           NSLog(@"%@", linkarray);

       }

   }

对于NSLog,我期望:

TabBarSample[40191:fb03] (
    (
    "http://domain.com/image1.jpg"
 ),
(
"http://domain.com/image2.jpg"
)
)

但我知道:

TabBarSample[40191:fb03] (
"http://domain.com/image1.jpg"
)
TabBarSample[40191:fb03] (
"http://domain.com/image2.jpg"
)

我做错什么了?

Answer 1

以每个循环创建新数组 :

 NSArray *linkarray = [[NSArray alloc] initWithObjects:articlePoint, nil];

相反,您想要在 llop 之外添加一个 NS Mutable 阵列,并在每个环圈中添加一个对象

   NSMutableArray *linkarray = [NSMutableArray array];
   NSArray *items = [channel elementsForName:@"item"];
   for (GDataXMLElement *item in items) {

       NSString *articlePoint = [item valueForChild:@"link"];
       [linkarray addObject:articlePoint];

       NSLog(@"%@", linkarray);

   }

如果增加数组令您混淆, 您应该将 NSLog 放在循环之后 :

   NSMutableArray *linkarray = [NSMutableArray array];
   NSArray *items = [channel elementsForName:@"item"];
   for (GDataXMLElement *item in items) {

       NSString *articlePoint = [item valueForChild:@"link"];
       [linkarray addObject:articlePoint];
   }

   NSLog(@"%@", linkarray);
   NSLog(@"count: %d", [linkarray count]);

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